Question 148

Four dice are thrown simultaneously. The probability that all of them show the same numbers is:

Solution

when 4 dices are thrown the number of total event occurs = 6*6*6*6= 1296

showing same number event are ={1,1,1,1] {2,2,2,2],{3,3,3,3],{4.4.4.4},{5,5,5,5},{6,6,6,6}

total number of favorable events are =6

Probility of getting same number on four dices are = $$\frac{number of favorable cases}{total number of events occurs}$$

P{e4}= $$\frac{6}{6^4}$$

P{e4}=$$\frac{1}{6^3}$$ answer

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