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Question 146
12 years ago the ratio between the ages of A and B was 3 : 4 respectively. The present age of B is 3 3/4 times of C’s present age. If C’s present agcy is 16 years then what is A’s present age ? (in years),
Solution
Current age of B = 3 $$\frac{3}{4}$$ times of C's age
current age of c = 16 years, Thus B's current age = $$\frac{15}{4}$$ * 16 = 60 years
12 years ago
A:B = 3:4
B's age = 48 years, thus A = 36 years
Hence current age of A = 36 + 12 = 48 years
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