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The following figure represents two biconvex lenses $$L_1$$ and $$L_2$$ having focal length $$10 \text{ cm}$$ and $$15 \text{ cm}$$ respectively. The distance between $$L_1$$ & $$L_2$$ is
Concept:
Condition for parallel output:
For rays emerging from $$L_1$$ to become parallel after $$L_2$$, the image formed by $$L_1$$ must lie at the focus of L_2.
Hence, separation between lenses:
D = $$f_1 + f_2$$ = 10 + 15 = 25
Final Answer:
25 cm
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