In letter clusters CHLQU, HMQVZ, AFJOS, the number of letters between the consecutive letters of the letter clusters are 4, 3, 4, 3 respectively.
In letter cluster MRVZF, the number of letters between the consecutive letters of the letter clusters are 4, 3, 3, 5 respectively.
$$\therefore\ $$MRVZF is the odd one among the given letter clusters.
Hence, the correct answer is Option C
Create a FREE account and get: