Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are:

 Step 1: Use relation

$$q=CV$$

 Slope of q-V graph = Capacitance

 Step 2: Identify graphs

• Steeper line (A) ⇒ parallel combination (higher capacitance)
• Less steep line (B) ⇒ series combination

 Step 3: Read values from graph

$$At\ V=10V:$$

• For A: q=500 μCq C

$$Cp​=\ \frac{\ 500}{10}=50μF$$

• For B: q=80 μCq 

$$C_s=\ \frac{\ 80}{10}​=8μF$$

 Step 4: Match with given capacitors

Let capacitors be C1=40 μF,  C2=10 μFC

• Parallel:

Cp=40+10=50 μFC

• Series:

Cs=40×1040+10=8 μFC