Let $$0 < \alpha < 1$$, $$\beta = \frac{1}{3\alpha}$$ and $$\tan^{-1}(1 - \alpha) + \tan^{-1}(1 - \beta) = \frac{\pi}{4}$$. Then $$6(\alpha + \beta)$$ is equal to:

A

6

B

7

C

8

D

9