### SSC JE Mechanical Engineering 23rd Jan 2018 Shift-1 Question 13

Instructions

In the following question, select the odd word from the given alternatives.

Question 13
Solution

The logic here is

G+2 = J, J+2 = M

H+2 = K, K+2 = N

M+2 = P, P+2=S

N+2 = Q, Q+3 = U

$$\therefore\$$NQU is the odd one among the given letter-clusters.

Hence, the correct answer is Option D