Question 126
The sum of all the 3 digit numbers which leave the remainder 1 when divided by 4 is
Solution
The First 3 digit number, which leaves a remainder of 1 when divided by 4 is 101 and the last is 997.
Total number of terms is 225. Hence applying the formula of AP and finding the sum
$$\frac{225}{2}\left(997+101\right)=\frac{1098}{2}\times\ 225=123525$$
Get AI Help
Create a FREE account and get:
- Download Maths Shortcuts PDF
- Get 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Session:Free CAT Mentorship
Phone:
Date:
Time:
Enter OTP
Didn't receive the OTP?
