Question 125

If $$x - 3$$ and $$x^4 - 2x^3 + 3x^2 - mx + 3$$, then $$m =$$

Solution

we have given that

$$x - 3$$ = 0 so we get x = 3 put the value of x in the following equation

$$x^4 - 2x^3 + 3x^2 - mx + 3$$ = 0

3^4 - 2$$\times{3^3}$$ + 3$$\times{3^2}$$ - m$$\times{3}$$ + 3 = 0

m$$\times{3}$$ = 57

m = 19 answer

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