Question 125

If $$x - 3$$ and $$x^4 - 2x^3 + 3x^2 - mx + 3$$, then $$m =$$

we have given thatΒ 

Β $$x - 3$$ = 0Β  so we get x = 3 put the value of x in the following equationΒ 

Β $$x^4 - 2x^3 + 3x^2 - mx + 3$$ = 0

3^4 - 2$$\times{3^3}$$ + 3$$\times{3^2}$$ - m$$\times{3}$$ + 3 = 0Β 

m$$\times{3}$$ = 57Β 

m = 19Β answerΒ 

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