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Instructions
In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give Answer If
a: x > y
b: x ≥ y
c: x < y
d: x ≤ y
e: x = y or the relationship can not be established
Solution
I : $$(x)^{2} = 961$$
=> $$x = \sqrt{961}$$
=> $$x = \pm 31$$
II : $$y=\sqrt{961}$$
=> $$y = 31$$
$$\therefore x \leq y$$
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