The top of a tower makes angles of elevation $$30^\circ$$ and $$45^\circ$$ at the two points A, B which are collinear with the foot of the tower on the level ground. If AB = 100 m, then the height of the tower, (in meters) is

A

$$50\sqrt{2}$$

B

$$50(\sqrt{3} + 1)$$

C

$$100(\sqrt{3} + 1)$$

D

$$100\sqrt{3}$$