39 43 51 60 87 110 167

Solution

This question has a very interesting pattern ,

43 - 39 = 4 = $$(2)^2$$

51- 43 =8 = $$(2)^3$$

60 - 51 = 9 = $$(3)^2$$

87 - 60 = 27 = $$(3)^3$$

As we can see that differences between consecutive terms are of the for $$(n)^2$$ and then $$(n)^3$$

So after 87 a number should come so that

y - 87 = 16 = $$(4)^2$$ which implies y = 103

But the number given is 110 and hence 110 is the odd one out .

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