The radius of the circular field is equal to the side of a square field. If the difference between the area of the circular field and area of the square field is 195 m2, what is the perimeter of the circular field ? (in m)
Let radius of circular field = side of square field = $$x$$ m
Acc. to ques, => $$(\pi x^2) - (x^2) = 195$$
=> $$x^2 (\frac{22}{7} - 1) = 195$$
=> $$x^2 \times \frac{15}{7} = 195$$
=> $$x^2 = 195 \times \frac{7}{15} = 91$$
=> $$x = \sqrt{91} \approx 9.5$$ m
$$\therefore$$ Perimeter of the circular field = $$2 \pi x$$
= $$2 \times \frac{22}{7} \times 9.5 = 59.71 \approx 60$$ m
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