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Instructions
The given histogram represents the frequency distribution of average runs scored by 50 selected players from a district in a local cricket tournament.
Solution
From the given Di According to question
$$ 15.6\times 6 = 93$$
$$25.5\times 10 = 255$$
$$35.5 \times 12 = 426 $$
$$45.5\times 16 = 728 $$
$$55.5\times 4 = 222 $$
$$ 65.5 \times 2 = 131 $$
then total 93+255+426+728+222+131 = 1855
therefore overal average = $$\dfrac {1855}{50}$$
$$\Rightarrow 37.1 $$ AnsÂ
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