Two cars A and B are running in the same direction. Car ‘A’ had already covered a distance of 60 kms, when car ‘B’ started running. The cars meet each other in 3 hours after car ‘B’ started running. What was the speed of car ‘A’ ?

Let the speed of car A be 'x' kmph and the speed of car B be 'y' kmph.
By the time car B started running, car A covered 60 Km.

Distance covered by B in three hours is 3y
Distance covered by A in three hours is 3x

So, 3y = 3x + 60 or y=x+20
Hence, the speed of B is 20 kmph more than the speed of A. As we don't know the speed of car B, we can't find the exact speed of car A. We can just infer that the speed of car A is 20 kmph less than the speed of car B.