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A child is looking for his father. He went 90 m in the East before turning to his right. He went 20 m before turning to his right again to look for his father at his uncle's place 30 m from this point. His father was not there. From there, he went 100 m to the North before meeting his father in a street. How far did the son meet his father from the starting point?
The child starts from point A and he moves 90 m in the east and reaches at B.
Now, from B he takes a right and moves 20 m and reaches at C.
Then, again he takes a right and moves 30 m to reach at D. (Uncle's place)
Now, he moves 100 m north of point D, and reaches at E.
We need to find the distance AE?
From the diagram, we know AEO forms a right-angled triangle.
AO = 60
EO = 80
Thus, $$AE^2=AO^2+EO^2$$
$$AE^2=60^2+80^2$$
AE = 100 m
