The ratio of diameter to height of a right circular cylinder is 6 : 5. If the diameter gets reduced by 25%, then its total surface area is reduced by 338.25 sq.meters. Then the circumference of the base of original cylinder is

A

$$8\sqrt{2}\pi$$

B

$$6\sqrt{7}\pi$$

C

$$4\sqrt{5}\pi$$

D

$$7\sqrt{3}\pi$$