The breadth of a rectangular plot is 75% of its length and the perimeter of the plot is 1050 m. Thenthe area. in square meters, of the plot is

Let, Length be l, breadth be  b

As per the condition given in the question,

$$b = l \times \dfrac{3}{4}$$

$$\Rightarrow 4b = 3l or 3l-4b = 0 ---------(i) $$ 

$$\Rightarrow  2(l+b) = 1050$$

$$\Rightarrow l+b = 525$$

$$\Rightarrow  l = 525 - b ------- (ii) $$ 

Put the value of "l' from equation (ii) in the equation (i)

$$ \Rightarrow 3(525 - b) - 4b = 0$$

$$ \Rightarrow 1575-3b-4b = 0$$

$$ \Rightarrow 1575 = 76$$

$$ \Rightarrow b = 225m ------(iii)$$

Put the value of b from equation (iii) in the equation (ii)

$$ l = (525-b)$$

$$ l = (525-225)$$

$$ l = 300m$$ ------------(iv)

Area of plot in square metres will be = l \times b 

Put the value of l and b from equation (iii) and (iv)

$$A = 300 \times 225$$

$$A = 67,500$$

Therefore, area of the plot is square metre is 67500 metres