In the MBA Programme of a B - School, there are two sections A and B. 1/4th of the students in Section A and 4/9th of the students in section B are girls. If two students are chosen at random, one each from section A and Section B as class representative, the probability that exactly one of the students chosen is a girl, is :
Probability of choosing a boy from Section A =Â 3/4
Probability of choosing a boy from Section B =Â 5/9
Probability of choosing a girl from Section A =Â 1/4
Probability of choosing a girl from Section B =Â 4/9
There are two cases.Â
Case 1: Boy from section A and girl from section B
Probabilty = $$\frac{3}{4}$$ x $$\frac{4}{9}$$
Case 1: Boy from section A and girl from section B
Probabilty = $$\frac{1}{4}$$ x $$\frac{5}{9}$$
Adding gives final probability =Â $$\frac{12}{36}$$ + $$\frac{5}{36}$$ = $$\frac{17}{36}$$Â
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