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A train takes 52 seconds to cross a bridge of length 204 m. if the same train takes 18 seconds to cross a sign board, find the length of the train. (in metre)
Let length of train = $$l$$ m and speed = $$s$$ m/s
Speed of train which takes 52 seconds to cross a bridge of length 204 m = $$s=\frac{204+l}{52}$$ -----------(i)
Also, $$s=\frac{l}{18}$$ --------------(ii)
Substituting value of $$s$$ from equation (ii) in (i), we get :
=> $$\frac{l}{18}=\frac{204+l}{52}$$
=> $$52l=(204\times18)+18l$$
=> $$52l-18l=34l=204\times18$$
=> $$l=\frac{204\times18}{34}=108$$
$$\therefore$$ Length of train = 108 m
=> Ans - (D)
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