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Let f be a function such that $$f(x) + 3f\left(\dfrac{24}{x}\right) = 4x$$, $$x \neq 0$$. Then $$f(3) + f(8)$$ is equal to
We are given $$f(x) + 3f\left(\dfrac{24}{x}\right) = 4x$$ for $$x \neq 0$$.
Substituting $$x = 3$$: $$f(3) + 3f(8) = 12$$ ... (i)
Substituting $$x = 8$$: $$f(8) + 3f(3) = 32$$ ... (ii)
Adding equations (i) and (ii): $$f(3) + 3f(8) + f(8) + 3f(3) = 12 + 32$$
$$4f(3) + 4f(8) = 44$$
$$f(3) + f(8) = 11$$
Hence, the correct answer is Option A.
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