When vector $$\vec{A} = 2\hat{i} + 3\hat{j} + 2\hat{k}$$ is subtracted from vector $$\vec{B}$$, it gives a vector equal to $$2\hat{j}$$. Then the magnitude of vector $$\vec{B}$$ will be:

A

$$\sqrt{5}$$

B

3

C

$$\sqrt{6}$$

D

$$\sqrt{33}$$