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Let's find the dimensions of angular momentum, latent heat, and capacitance step by step.
First, angular momentum is given by the formula: angular momentum = radius × linear momentum. Radius has the dimension of length, so its dimension is $$L$$. Linear momentum is mass × velocity. Mass has dimension $$M$$, and velocity is distance over time, so its dimension is $$LT^{-1}$$. Therefore, linear momentum has dimension $$M \times LT^{-1} = MLT^{-1}$$. Now, angular momentum = radius × linear momentum = $$L \times MLT^{-1} = ML^2T^{-1}$$.
Second, latent heat is the heat energy absorbed or released per unit mass during a phase change. Heat energy has the same dimension as work, which is force × distance. Force is mass × acceleration, so force has dimension $$M \times LT^{-2} = MLT^{-2}$$. Work = force × distance = $$MLT^{-2} \times L = ML^2T^{-2}$$. Latent heat = heat energy / mass = $$ML^2T^{-2} / M = L^2T^{-2}$$.
Third, capacitance is defined as charge divided by voltage. Charge has dimension $$AT$$ (since current I is charge per time, so charge = current × time). Voltage (potential difference) is work done per unit charge, so voltage = work / charge = $$ML^2T^{-2} / AT = ML^2T^{-3}A^{-1}$$. Therefore, capacitance = charge / voltage = $$AT / (ML^2T^{-3}A^{-1}) = AT \times M^{-1}L^{-2}T^{3}A = M^{-1}L^{-2}T^{4}A^{2}$$.
So, the dimensions are:
Now, comparing with the options:
Hence, the correct answer is Option D.
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