Join WhatsApp Icon JEE WhatsApp Group
Question 1

A body is moving with constant speed, in a circle of radius 10 m. The body completes one revolution in 4 s. At the end of 3rd second, the displacement of body (in m) from its starting point is:

The body moves in a circle of radius $$R = 10$$ m with period $$T = 4$$ s.

At $$t = 3$$ s, the fraction of revolution completed:

$$ \frac{t}{T} = \frac{3}{4} $$

This means the body has covered $$\frac{3}{4}$$ of a full circle, i.e., $$270°$$.

If the body starts at the top of the circle (say at angle $$0°$$), after $$270°$$ it is at the position that is $$90°$$ short of completing the circle.

The displacement is the straight-line distance from the starting point to the current position. For a $$270°$$ arc (or equivalently $$90°$$ measured the other way), the chord length is:

Using the chord formula $$d = 2R\sin(\theta/2)$$ where $$\theta = 270°$$:

$$ d = 2 \times 10 \times \sin(135°) = 20 \times \frac{\sqrt{2}}{2} = 10\sqrt{2} \text{ m} $$

Alternatively, the starting and ending points are separated by $$90°$$ on the circle (since $$360° - 270° = 90°$$), forming two perpendicular radii. The displacement = $$\sqrt{R^2 + R^2} = R\sqrt{2} = 10\sqrt{2}$$ m.

Get AI Help

Video Solution

video

50,000+ JEE Students Trusted Our Score Calculator

Predict your JEE Main percentile, rank & performance in seconds

Ask AI

Ask our AI anything

AI can make mistakes. Please verify important information.