SSC CGL Tier l 2023 Question Paper Shift 4 (July 18th)
For the following questions answer them individually
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 61
In a $$\triangle ABC$$, if $$\angle A= 90^{\circ}$$, AC= 5 cm, BC= 9 cm and in $$\triangle PQR, LP= 90^{\circ}$$, PR = 3 cm, QR= 8 cm, then:
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 62
The following diagram shows the rainfall over two years. Which of the following months shows the highest percentage change in rainfall?
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 63
If $$ p = \frac{\sqrt{2} + 1}{\sqrt{2} - 1}$$ and $$q = \frac{\sqrt{2} - 1}{\sqrt{2} + 1}$$, then find the value of $$\frac{p^{2}}{q} + \frac{q^{2}}{p}$$.
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 64
Find the exact value of $$\cos 120^{\circ}$$.
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 65
A cone and a cylinder with equal radii have equal volumes. The ratio of their heights is:
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 66
Observe the given figure. The distance between the two centers AB is
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 67
Quantity of various food items used by a restaurant during 4 months of a year (in kg).
What is the average quantity of food item C used during all the 4 months together?
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 68
Find the fourth proportional of 144, 192 and 216.
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 69
Simplify the following expression.
$$\frac{7}{10} \div \frac{3}{7}$$ of $$\left(2\frac{3}{10} + 2\frac{3}{5}\right) + \frac{1}{5} \div 1\frac{2}{5} - \frac{2}{7}$$
SSC CGL Tier l 2023 Shift 4 (July 18th) - Question 70
Using $$\tan (A - B) = \frac{\tan A - \tan B}{1+\tan A \tan B}$$, find the value of $$\tan 15^{\circ}$$.
