SSC CGL 3rd March 2020 Shift-2

A can complete a certain piece of work in 40 days. B is 25% more efficient than A and C is 28% more efficient than B. They work together for 5 days. The remaining work will be completed by B alone, in:

A race track is in the shape of a ring whose inner and outer circumferences are 440 m and 506 m,respectively. What is the cost of levelling the track at ₹6/m$$^2$$? (Take $$\pi = \frac{22}{7}$$ )

The compound interest on a certain sum at 10% p.a. for $$2\frac{1}{3}$$ years is ₹1,201.60, interest compounded yearly. The sum is:

The given table represents the number of engineers recruited by four companies A, B, C and D over the years. Study the table carefully and answer the question that follows.

The ratio of the total number of engineers recruited by companies A and B in 2015 and 2018 to the total number of engineers recruited by C and D in 2014 and 2018,is:

Two bottles of the same capacity are 35% and $$33 \frac{1}{3} \%$$ full of orange juice, respectively. They are filled up completely with apple juice and then the contents of both bottles are emptied into another vessel. The percentage of apple juice in the mixture is:

In $$\triangle$$ ABC, AB = AC and AL is perpendicular to BC at L. In $$\triangle$$ DEF, DE = DF and DM is perpendicular to EF at M.If (area of $$\triangle$$ ABC) (area of $$\triangle$$ DEF) = 9:25, then $$\frac{DM + AL}{DM - AL}$$ is equal to:

The given table represents the number of engineers recruited by four companies A, B, C and D over the years. Study the table carefully and answer the question that follows.

The number of the years in which the number of engineers recruited by company D is less than the average number of engineers recruited by B in the given six years,is:

The value of $$\left(18 \div 2 of \frac{1}{4}\right) \times \left(\frac{2}{3} \div \frac{3}{4} \times \frac{5}{8}\right) \div \left(\frac{2}{3} \div \frac{3}{4} of \frac{3}{4}\right)$$ is:

If $$2 \sin \theta + 15 \cos^2 \theta = 7, 0^\circ < \theta < 90^\circ$$, then $$\tan \theta + \cos \theta + \sec \theta =$$

$$\triangle$$ ABC is an equilateral triangle and AD $$\perp$$ BC, where D lies on BC. If AD = $$4\sqrt{3}$$ cm, then what is the perimeter (in cm) of $$\triangle$$ABC?