For the following questions answer them individually
If $$x\sin^{2} 60^{\circ}-\frac{3}{2} \sec60^{\circ} \tan^{2}30^{\circ}$$ + $$\frac{4}{5}\sin^{2}45^{\circ}\tan^{2}60^{\circ}=0$$ then x is
If $$7\sin\alpha=24 \cos\alpha;0<\alpha<\frac{\pi}{2},$$ then the value of $$14\tan\alpha-24\cot\alpha$$ is equal to
∠ACB is an angle in the semicircle of diameter AB = 5 and AC : BC = 3 : 4. The area of the triangle ABC is
A, B and C are three points on a circle such that the angles subtended by the chords AB and AC at the centre 0 are 90° and 110° respectively. Further suppose that the centre ‘0’ lies in the interior L BAC. The L BAC is
If the lengths of the sides AB, BC and CA of a triangle ABC are 10 cm, 8 cm and 6 cm respectively and if M is the mid - point of BC and MN II AB to cut AC at N, then the area of the trapezium ABMN is equal to
A type of graph in which a circle is divided into sectors such that each sector represents a proportion of the whole is a
The value of x which satisfies the equation $$2 \csc^{2} 30^{\circ}+x \sin^{2}60^{\circ}-\frac{3}{4}\tan^{2}30^{\circ}=10$$ is
If $$2\sin\theta+\cos\theta-\frac{7}{3}$$ then the value of $$(\tan^{2}\theta-\sec^{2}\theta)$$ is
Day-wise Structured & Planned Preparation Guide
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