SSC CGL 2011 Question Paper Tier 1 - Shift 1 (June 19th)

Instructions

For the following questions answer them individually

SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 101


p = 124 , $$\sqrt[3]{p(p^2 + 3p + 3) + 1}$$ = 

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 102


Find x given $$\sqrt{1 - \frac{x^3}{100}} = \frac{3}{5}$$

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 103


I multiplied a natural number by 18 and another by 21 and added the products. Which one of the following could be the sum?

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 104


The product of two numbers is 45 and their difference is 4. The sum of squares of the two numbers is

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 105


$$\sqrt{8 + \sqrt{57 + \sqrt{38 + \sqrt{108 + \sqrt{169}}}}}$$

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 106


The square root of $$14 + 6\sqrt{5}$$

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 107


When 231 is divided by 5 the remainder is

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 108


$$1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}}}$$

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 109


The unit digit in the product $$122^{173}$$ is

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SSC CGL 2011 Tier 1 - Shift 1 (June 19th) - Question 110


$$\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}+\frac{\sqrt{3}+1}{\sqrt{3}-1}$$ = 

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