[Download PDF] SBI 2004 PO Paper with Solutions

Instructions

In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.

SBI 2004 PO - Question 81

I. $$a^{2}+5a+6=0$$
II. $$b^{2}+3b+2=0$$

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Solution

SBI 2004 PO - Question 82

I. $$2a^{2}+3a+1=0$$
II. $$12b^{2}+7b+1=0$$

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Solution

SBI 2004 PO - Question 83

I. $$a^{2}=4$$
II. $$b^{2}=9$$

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Solution

SBI 2004 PO - Question 84

I. $$6a^{2}-25a+25=0$$
II. $$15b^{2}-16b+4=0$$

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Solution

SBI 2004 PO - Question 85

I. $$4a^{2}-20a+21=0$$
II. $$2b^{2}-5b+3=0$$

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Solution

Instructions

What approximate value will come in place of the question mark (?) in the following equations ?

SBI 2004 PO - Question 86

125% of 4875 + 88.005 $$\times$$ 14.995 =?

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Solution

SBI 2004 PO - Question 87

$$127.001 \times 7.998 + 6.05 \times 4.001$$ = ?

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Solution

SBI 2004 PO - Question 88

$$1010\div36+187\times20.05$$=?

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Solution

Instructions

For the following questions answer them individually

SBI 2004 PO - Question 89

What will come in the place of question mark (?) in the following equation ?
$$16^{7.5}\div8^{3.5}\div2^{7.5}$$=?

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Solution

SBI 2004 PO - Question 90

Present ages of Seema and Naresh are in the respective ratio of 5:7. Five years hence the ratio of their ages become 3: 4 respectively. What is Naresh’s present age in years ?

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Solution

BANKING Content

SBI 2004 PO

SBI 2004 PO

SBI 2004 PO - Question 81

SBI 2004 PO - Question 82

SBI 2004 PO - Question 83

SBI 2004 PO - Question 84

SBI 2004 PO - Question 85

SBI 2004 PO - Question 86

SBI 2004 PO - Question 87

SBI 2004 PO - Question 88

SBI 2004 PO - Question 89

SBI 2004 PO - Question 90

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