NTA JEE Mains 8th April 2024 Shift 1

Two charged conducting spheres of radii $$a$$ and $$b$$ are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

In the given circuit, the terminal potential difference of the cell is :

Paramagnetic substances: A. align themselves along the directions of external magnetic field. B. attract strongly towards external magnetic field. C. has susceptibility little more than zero. D. move from a region of strong magnetic field to weak magnetic field. Choose the most appropriate answer from the options given below:

A LCR circuit is at resonance for a capacitor $$C$$, inductance $$L$$ and resistance $$R$$. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:

Critical angle of incidence for a pair of optical media is $$45°$$. The refractive indices of first and second media are in the ratio:

A proton and an electron are associated with same de-Broglie wavelength. The ratio of their kinetic energies is: (Assume $$h = 6.63 \times 10^{-34} \text{ J s}$$, $$m_e = 9.0 \times 10^{-31} \text{ kg}$$ and $$m_p = 1836 \; m_e$$)

Average force exerted on a non-reflecting surface at normal incidence is $$2.4 \times 10^{-4} \text{ N}$$. If $$360 \text{ W/cm}^2$$ is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is:

Binding energy of a certain nucleus is $$18 \times 10^8 \text{ J}$$. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:

The output Y of following circuit for given inputs is :

The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest division on the main scale is equal to $$1 \text{ mm}$$. The main scale reading is $$2 \text{ cm}$$ and second division of vernier scale coincides with a division on main scale. If mass of the sphere is $$8.635 \text{ g}$$, the density of the sphere is: