Question 99
A train of 270 metres long crosses a platform of 390 metres length in 33 seconds. The speed of the train (in kmph) is
Solution
The total distance travelled by the train in 33 seconds = 270 + 390 meters = 660 meters
Speed of train (in m/s) = 660/33 = 20 m/s
Hence, speed in kmph = 20*(18/5) = 72 kmph
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