Car A starts at 8 am from the place P, with a speed of 65 kmph. AnothercarB starts at 9 am from the same place P. and follows the car A with a speed of 70 kmph. Then the meeting time of the cars A and B is
Car A starts at 8AM with the speed of $$65kmph$$
Car B starts at 9AM with the speed of $$70kmph$$
Both starts from the point P,
Let after the time t, both the car will meet.
$$d=65\times t---------(i)$$
$$d=70\times (t-1)-------(ii)$$
From the equation (i) and (ii)
$$65\times t=70\times t-70$$
$$5\times t=70$$
Hence t=14 hour.
Hence both the car will meet 10PM
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