Question 95

A hemispherical metallic solid is melted and recast into a cone of equal radius 'R'. If the height of the cone is H, then:

Solution

When we change shape of a solid figure, volume remains constant

Vol of hemisphere = Vol of cone

$$\frac{2\times R^3}{3}\pi=\frac{1\times R^2}{3}\pi\times H$$

2R=H

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