Question 95

A and B together can complete a task in 20 days. B and C together can complete the same task in 30 days. A and C together can complete the same task in 40 days. What is the respective ratio of the number of days taken by A when completing the same task along to the number of days taken by B when completing the same task alone?

Solution

Let the work completed by A in one day = $$\frac{1}{A}$$
Let the work completed by B in one day = $$\frac{1}{B}$$
Let the work completed by C in one day = $$\frac{1}{C}$$
$$\frac{1}{A}$$ + $$\frac{1}{B}$$ = $$\frac{1}{20}$$
$$\frac{1}{B}$$ + $$\frac{1}{C}$$ = $$\frac{1}{30}$$
$$\frac{1}{A}$$ + $$\frac{1}{C}$$ = $$\frac{1}{40}$$
Solving the above equations we get $$\frac{1}{A}$$ = $$\frac{1}{24}$$ 
                                                                    A = 24
                                               Similarly B = 120 and C = 60
                                                         


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