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Each of the six friends, I, J, K, L, M and N working in an office handles different number of projects in a month. I handles the second lowest number of projects. K handles more projects than L and M but less than J. J did not handle the maximum number of projects. M did not handle the minimum number of projects. The one who handle the third highest number of projects handled 31 projects. L handled 12 projects.
I handles the second lowest number of projects.
K handles more projects than L and M but less than J, => J > K > L , M
J did not handle the maximum number of projects, => J handled 2nd highest number of projects and K handled 3rd highest.
M did not handle the minimum number of projects, => L handled the least number of projects and N handled the highest.
Combining above statements, we get :
$$\therefore$$ N > J > K > M > I > L
Number of projects handled by K = 31 and L = 12
The only true statement is that no one handles more projects than N.
=> Ans - (A)
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