What is the difference between the total number of students who prefer beverage A and C together and the total number of students who prefer beverage D and F together?
Number of students preferring beverages A and C = 22 + 4 = 26% of 6800 = $$\frac{26}{100}$$ x 6800 = 1768
Number of students preferring beverages D anf F = 34 + 6 = 40% of 6800 = $$\frac{40}{100}$$ x 6800 = 2720
Difference = 952
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