The distance between two points A and B is 84 km. Two persons start at the same time, one travelling from A towards B and the other travelling from B towards A. If their respective speeds are 36 km/h and 27 km/h and they meet at point C between A and B, then find the value of (CA/(CA ‒ CB).

Since the two persons are traveling toward each other, their relative speed will be (36+27)kmph, which is 63kmph. 

Now, they will meet at t= $$\ \frac{\ 84}{63}$$ hours, which is $$\ \frac{\ 4}{3}$$ hours.

Now, in $$\frac{CA\ }{(CA‒CB)\ }$$, CA is the distance traveled at a speed of 36 kmph in 't' hours and CB is (84-CA)

In 't' hours, CA= $$36\times\frac{\ 4}{3}$$, which is 48 km. 

Similarly, CB= 84-48= 36 km

Putting these values in (CA/(CA ‒ CB), we get the answer as 4.