Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; $$T_3 > T_2 > T_1$$ as:
For an isothermal process involving an ideal gas, we have $$PV = nRT = \text{constant}$$.
This gives the relation $$P = \frac{nRT}{V}$$, which is a rectangular hyperbola in the P-V plane.
Key properties of isothermal curves (isotherms) on a P-V diagram:
1. Each isotherm is a rectangular hyperbola.
2. For a higher temperature, the hyperbola is farther from the origin.
3. At any given volume, a higher temperature gives a higher pressure (since $$P = \frac{nRT}{V}$$).
Since $$T_3 > T_2 > T_1$$, the isotherm for $$T_3$$ should be the outermost curve (farthest from origin), $$T_2$$ in the middle, and $$T_1$$ closest to the origin.
The correct graph shows rectangular hyperbolas that do not intersect, with $$T_3$$ being the highest curve.
The answer is Option A.
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.