If two is added to the first three digits and three is subtracted from the last three digits in the number 657489, how many digits in the number thus formed will be multiples of 3 ?
Number : 657489
If two is added to the first three digits and three is subtracted from the last three digits, Number
= $$(6+2) (5+2) (7+2) (4-3) (8-3) (9-3)$$
= $$879156$$
Thus, only 2 digits are multiples of 3
=> Ans - (C)
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