If the digits of a two-digit number are interchanged the newly formed number is more than the original number by 18 and sum of the digits is 8, then what is the original number?
Let the two-digit number be 'xy'
The number after interchanging the digits = yx
Given that x + y = 8
And 10y + x = 18 + 10x + y
y - x = 2
On solving both the equations, we get x = 3, y = 5
$$\therefore$$ The number is 35.
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