Question 88
If $$A, B$$ and $$C$$ are three points on a circle, where $$BC$$ is the diameter and $$AC = AB = 5\sqrt{2}Â cm$$. Find the radius of the circle.
Solution
$$BC$$ is the diameter and $$AC = AB = 5\sqrt{2}Â cm$$
$$ BC^2 = AB^2 + AC^2 $$
      = $$(5\sqrt{2})^2 + (5\sqrt{2})^2 $$
      = $$ 25 \times 2 \times 2 $$
       = 100
BC = 10 cm , diameter of circle
radius =$$ \frac{10}{2} $$
      = 5 cm
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