Question 87

If A and B are complementary angles, then find the value of $$\cos A \cos B - \sin A \sin B$$.

Solution

If A and B are complementary angles then

A+B = 90

$$\cos A \cos B - \sin A \sin B$$.

we know that

$$cos(A+B)=\cos A \cos B - \sin A \sin B$$.

$$ $$cos(A+B)

put value A+B=90

$$cos90=0$$

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