A tap A fills a tank in 30 hours. Another tap B fills the tank in 24 hours. If the taps are opened for one hour each alternately, in how many hours would the tank be full?
In one hour, A fills 1/30th of the tank
In one hour, B fills 1/24th of the tank
In two hours, A and B alternately fill 1/30 + 1/24 = 4/120 + 5/120 = 9/120 = 3/40th of the tank
Hence, they will take 2/(3/40) = 80/3 hours to fill the tank.
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