Question 85

A car travels at $$\frac{8}{7}$$ times its usual speed and reaches the destination 15 minutes early. Then the time taken by the car in hours to reach its destination with its usual speed is

Solution

New Speed of car is 8/7 of old speed 

So new time is 7/8 of old time 

8-7=1 unit =15 min early 

So  original time is 8×15=120 min or 2 hr


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