Question 85

A car travels at $$\frac{8}{7}$$ times its usual speed and reaches the destination 15 minutes early. Then the time taken by the car in hours to reach its destination with its usual speed is

Solution

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New Speed of car is 8/7 of old speed 

So new time is 7/8 of old time 

8-7=1 unit =15 min early 

So  original time is 8×15=120 min or 2 hr

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