Question 85

A car travels at $$\frac{8}{7}$$ times its usual speed and reaches the destination 15 minutes early. Then the time taken by the car in hours to reach its destination with its usual speed is

New Speed of car is 8/7 of old speedΒ 

So new time is 7/8 of old timeΒ 

8-7=1 unit =15 min earlyΒ 

SoΒ  original time is 8Γ—15=120 min or 2 hr

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