An arithmetic progression is written in the following way:

The sum of all the terms of the $$10^{th}$$ row is _____

Correct Answer: 1505

First term of row (n):
$$a_n=2+3\cdot\frac{(n-1)n}{2}$$

For (n=10):
$$a_{10}=137$$

Sum:
$$S_{10}$$= $$\frac{10}{2}$$($$2\cdot137+9\cdot3$$)

$$S_{10}=\frac{10}{2}(274+27)$$
$$S_{10}=1505$$

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