[Solved] Let a = 1 + \\frac{^2C_2}{3!} + \\frac{^3C_2}{4!} + \\frac{^4C_2}{5!} + \\ldots, b = 1 + \\frac{^1C_0 + ^1C_1}{1!} + \\frac{^2C_0+^2C_1+^2C_2}{2!} + \\frac{^3C_0+^3C_1+^3C_2+^3C_3}{3!} + \\ldots. Then \\frac{2b}{a^2} is equal to ______. - - NTA JEE Mains 04th April 2024 Shift 1