$$\sqrt[4]{17+12\sqrt{2}}=\sqrt[4]{9+8+12\sqrt{2}}$$
$$=\sqrt[4]{3^2+\left(2\sqrt{2}\right)^2+2\left(3\right)\left(2\sqrt{2}\right)}$$
$$=\sqrt[4]{\left(3+2\sqrt{2}\right)^2}$$
$$=\sqrt{3+2\sqrt{2}}$$
$$=\sqrt{1+2+2\sqrt{2}}$$
$$=\sqrt{1^2+\left(\sqrt{2}\right)^2+2\left(1\right)\left(\sqrt{2}\right)}$$
$$=\sqrt{\left(1+\sqrt{2}\right)^2}$$
$$=1+\sqrt{2}$$
Hence, the correct answer is Option B
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