Question 78

The sum of the ages of 4 children born at the intervals of 4 years is 48. Find the age of the youngest child.

Solution

Let the age of the smallest child be x

therefore, the age of the other children will be

x,x+4, x+8, x+12 (given that each child is born at the interval of 4 years)

but the sum of all the years of children of equal to 48

=> x + (x+4) + (x+8) + (x+12) =48

= x+x+4+x+8+x+12= 48

= 4x + 24= 48

= 4x=24

= x=6= age of the smallest child

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