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Study the table and graph answer the given questions:
Distribution (degree wise) of students in five schools A, B, C, D and E
Total number of students (boys and girls) in 5 schools = 5400
The average number of girls in schools D and E is approximately what per cent less than the number of students in school C?
Total number of students in D and E =Â $$\frac{105\ +\ 54}{360}\times\ 5400\ =\ 2385$$.
Total number of girls in D and E = 2385 - (450+1017) = 918.
The average number of girls in schools D and E = 918/2 = 459.
Number of students in C =Â $$\frac{64}{360}\times\ 5400\ =\ 960$$.
The required percentage =Â $$\frac{960-459}{960}\times\ 100\ \approx\ 52.2\%$$.
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