In the following questions two equations numbered I and
II are given. You have to solve both the equations and
a: if x > y
b: if x ≥ y
c: if x < y
d: if x ≤ y
e: if x = y or the relationship cannot be established.
I. $$x^{2}=49$$
II. $$y^{2}-4y-21=0$$
$$x^2 = 49$$
$$x = -7, 7$$
$$y^2-4y-21 = 0$$
$$(y-7)(y+3) = 0$$
$$y = -3, 7$$
Hence, pairs of (x,y) are (-7,-3), (-7,7), (7,-3) and (7,7). Hence, in some x is less than y and in some x is greater than y. Thus no relation can be established.
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